(B^2-b-b-29)/(b-6)

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Solution for (B^2-b-b-29)/(b-6) equation:


D( x )

b-6 = 0

b-6 = 0

b-6 = 0

b-6 = 0

x naleu017Cy do R

x belongs to the empty set

(B^2-b-b-29)/(b-6) = 0

x belongs to the empty set

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